What is the estimated total number of electrons present in 100g of water? How much is the total negative charge carried by these electrons?

It is known that every mole of any substance contains Avogadro numbers of atoms/ions/electrons/molecules. This Avogadro quantity is equal to 6.022×1023.

Mass of 1 mole of water is 18 g as H2O has one atom of oxygen and two atoms of hydrogen and you can calculate the mass.hence 18 g of H2O has Avogadro number of electrons.Which is defined as the definition of 1 mole.hence 1 g of water contains 6.022×10^23/18 number of electrons and from this you can say that 100 g of water contains 100x(6.022×10^23/18)number of electrons and total charge is equal to one electronic charge multiplied by above number of electrons that comes out to be present in 100 g of water that is

1.6×10^-19x(100x(6.022×10^23/18)) coulombs.

Thanks.

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